Tuesday, June 23, 2009

problem on force and acceleration

Topic :-Force and Acceleration

The velocity of a moving object is the rate at which its position or location changes and is measured in units of length per time,in other words,
when we apply some force on an object then the acceleration will increase accordingly.So the force and acceleration are directly proportional to each other.


Queston:-An electron in a television picture tube moves towards the front of the tube with a speed of 8.0x10^6m/s along the x axis surrounding the neck of the tube are coils of wire that create a magnetic field of magnitude 0.0025T, directed at an angle of 60degrees to the x axis and lying in the x y plane . Calculate the magnetic force on and acceleration of the electron (charge of electron -1.6x10^-19C and mass is 9.11x10^-31kg. find the net?

Answer:

Given
Net force=2.77*10-15 N,
Acceleration=.304*1016m/sec^2


Here,
V=8.0x106m/s
B=0.0025T(magnetic field's of magnitude)
Q=charge of electron -1.6x10-19C
Mass = 9.11x10-31kg

The formula to find force is
F=q (V*B)

=QVB sin θ
= QVB sin 60
=2.77*10-15 N

So,
Net force=2.77*10^-15 N
Direction = Z direction
                              
F
Acceleration=------
m

= .304*1016m/sec^2

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1 comment:

  1. (b) Show that the period is independent of both the speed and the radius.
    (c) Find the angular speed and hence the period of motion around the neck of the tube.
    (d) What is the magnitude of the electrical potential difference that accelerates the electron through the magnetic field?

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